Answer:
87.08% percentage of families spend more than $4000 annually on food and drink
Step-by-step explanation:
Given -
average annual expenditure on food and drink for all families is $5700
Mean 
= 5700
standard deviation 
= 1500
Let X be the no of families spend annually on food and drink
percentage of families spend more than $4000 annually on food and drink =
= 
= 
Using 
= 1 - 
= 1 - .1292
= .8708
= 87.08%
-4x+2=9 would be the answer for this equation
B. is the answer hope I got it right: )
Answer:
2.28%
Step-by-step explanation:
mean = 5 years = 60 months
standard deviation = 6 months
X = number of years the tires will last
P = probability of ...
z = z-score
6 years = 72 months
z = (# of months - mean) / standard deviation
z = (72 - 60)/6
z = 12/6
z = 2
P(X > 72) = 1 - P(X < 72)
= 1 - P(z < 2)
(using a Standard Normal Probabilities Table we can see that P(z < 2) = .9772)
So:
= 1 - .9772
= 0.0228 OR 2.28%
Answer:
-9
Step-by-step explanation:
Simplify the following:
7 - 8/4 (3^2 - 1)
Hint: | Evaluate 3^2.
3^2 = 9:
7 - 8/4 (9 - 1)
Hint: | Subtract 1 from 9.
9 - 1 = 8:
7 - 2×8
Hint: | Divide 8 by 4.
8/4 = (4×2)/4 = 2:
7 - 2×8
Hint: | Multiply -2 and 8 together.
-2×8 = -16:
7 + -16
Hint: | Subtract 16 from 7.
7 - 16 = -9:
Answer: -9
