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OLga [1]
3 years ago
12

company that manufactures cookware has conducted numerous trials to see which metal needs the least amount of energy (measured i

n Joules, J) to be raised to high temperatures, and records the averages in a table. Which claim will this company most likely make? Aluminum pans are the most energy-efficient cookware. Copper pans are the most energy-efficient cookware, but they cost the most. Iron pans require less energy to heat up than copper frying pans, but they cost less. Copper pans require the most energy to heat up.
SAT
2 answers:
LenKa [72]3 years ago
5 0

Requirements that the cookware manufacturing company is looking for :

a metal that needs least amount of energy to be raised to high temperatures. (Given)

We are provided with the following options :

1. Aluminium pans are most energy efficient cookwares.

2. Copper pans are the most energy-efficient cookware, but they cost the most.

3. Iron pans require less energy to heat up than copper frying pans, but they cost less.

4. Copper requires the most energy to heat up.

We see that, copper requires less energy to heat up . So, option 4 is ruled out.

Also, iron pans take up less heat than copper, but not the best. So, option 3 is ruled out.

And, Aluminium is energy efficient but not as good as copper.

Hence the company will claim, "Copper pans are the most energy efficient cookwares, but they cost the most. "


Ivenika [448]3 years ago
4 0

Copper pans are the most energy-efficient cookware, but they cost the most.

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This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

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B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

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Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

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Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

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