Answer:
denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)
Explanation:
Denial-of-service attack -
It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .
The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .
In case of the distributed denial-of-service attack , the flooding is done by many different sources .
Hence , from the given scenario of the question ,
The correct answer is denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .
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The indices of the internal array elements that hold the remaining elements is c) 2 to 4
<h3>Calculations and Parameters:</h3>
For us to create a capacity of 10 for the queue, we would enqueue:
We would create a queue of capacity 10:
<h3>Queue q(10);</h3>
We add elements/enqueue 5 elements to the queue :
- q.queueEnqueue(10);
- q.queueEnqueue(5);
- q.queueEnqueue(8);
- q.queueEnqueue(9);
- q.queueEnqueue(2);
Printing this would give:
q. queueDisplay()
10, 5, 8, 9, 2
Next, we would remove elements/dequeue 2 elements from the queue :
q. queuedequeue();
q. queuedequeue();
Printing it would be:
q. queueDisplay()
8 ,9, 2
Observing this, the deletion/dequeue starts from the front/first index.
The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4
Read more about arrays and enqueue here:
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Answer:
The client
Explanation:
On a client/server network, THE CLIENT computer initiates the process of assigning an IP address through DHCP. This is because "The Client" computer will serve as the Domain controller in which other computers of the network can find. Hence, The Client computer initiates the process of assigning IP addresses through DHCP to achieve this.
Though, in some case. A user can manually assign the IP address to computer if it is not through DHCP
