All categories

1 year ago

What is boot sector virus

Computers and Technology

1 answer:

Galina-37 [17]1 year ago

4 0

Answer:

Boot Sector virus is when a virus infects the Boot Sector of a hard disk. A Boot Sector is the initial files necessary to start an OS and other bootable programs. It is typically infected by these viruses when started with infected floppy disks, however the boot virus does not have to be successful to infect your computer. Once infected, the virus tries to infect every other disk.

Hope this helps!

You might be interested in

vichka [17]

Reddit
Buzzfeed
Ohmygossip
Unitedbypop
(YOU KNOW YOU COULD JUST TYPE THAT IN GOOGLE)

5 0

3 years ago

What are Important points to include about preventing the download of malware?

Natasha2012 [34]

Check if it’s a viable site, the browser will usually warn you if the site or file as to what you’re downloading from is dangerous.

7 0

3 years ago

Organizations following Waterfall methodology usually begin with requirements gathering, in which the development team attempts

Aleks04 [339]

Answer:

Project teams do smaller portions of the entire project in small sprints.

Teams can interact to handle different steps simultaneously if needed.

Documentation is still required to keep everybody on track. This documentation allows teams to keep control over what version of the project they are working on and how the project has changed along the way.

As an approach to rapid development, the focus is on development rather than planning, enabling teams to start work more quickly.

hope this helps you

7 0

3 years ago

The _____ element, a hypertext markup language (html) metadata element, contains a collection of metadata elements that describe

Butoxors [25]

The "head" element, a hypertext markup....
Missing word is head

5 0

3 years ago

Read 2 more answers

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

What is boot sector virus​

What is boot sector virus