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podryga [215]
3 years ago
9

PLZ HELP ASAP

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
Answer is D:
e + 5 = 3e - 11

2e = 16
e = 8

Ella is 8 years old
Jamie is 8+5 = 13 years old
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How do you show your work for this problem?
laiz [17]

Answer:

i cant see it

Step-by-step explanation:

7 0
3 years ago
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Please help Geometry!!<br><br> Please help me with number 4, not sure how to answer it
lilavasa [31]
All of the values follow the same formula rule. n= n x (n-1) / 2
Use this formula to find the number of segments. 
4 0
3 years ago
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
2 years ago
Without calculating the answer for 5 1/5 * 2/5 be larger or smaller than 5 1/5​
solniwko [45]

Answer:

Evidently, without the calculating 5 1/5 times 2/5 would be larger than 5 1/5 since you are already gonna multiply 2/5 and that would make it larger.

Hope this helps!

Branliest would be appreciated :DD

Step-by-step explanation:

4 0
3 years ago
5-1-9/3-9 What do I do?
Contact [7]
Rewrite it to simplify using order of operations.

P E M D A S
() ^2 × ÷ + -

So nw it's
5-1-(9÷3)-9

no now it's
(5-1)-(3-9)
4-(-6) I wrote the negative in parentheses to show its not an additional subtraction sign. also if you look it's sort of a plus sign. so when you subtraction (-6) from 4 it's actually 4+6

4-(-6)=10.

that's what I got. hope this helps.
7 0
3 years ago
Read 2 more answers
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