12.054 compared to 12.54 need to know
1 answer:
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Answer:
vertex = (- 1, 1 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = x² + 2x + 2 ← is in standard form
with a = 1 and b = 2 , then
x = - = - 1
substitute x = - 1 into the equation for y- coordinate of vertex
y = (- 1)² + 2(- 1) + 2 = 1 - 2 + 2 = 1
vertex = (- 1, 1 )
Answer:
its the second one
Step-by-step explanation:
The correct description of the graph:
<em>"One curve opens up and to the right in quadrant 1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
<h3>Which graph is the graph of the given functions?</h3>
Here we have the function:
The graph of this function can be seen below:
Then we can see that a curve opens up on quadrant 1, and down on quadrants 2 and 3 (it pass throw quadrant 1 for a little bit).
Then the correct option is:
<em>"One curve opens up and to the right in </em><em>quadrant </em><em>1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
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If you want to learn more about rational functions:
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