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3 years ago

Determine whether p^2-40 is a difference of two squares. Yes No

1 answer:

7 0

Answer: No

p^2 is a perfect square
40 is not a perfect square
p^2 - 40 is not a difference of two squares since 40 is not a perfect square

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Is 2,359 × 1,580 even or odd?

Nataly_w [17]

This will be even! You don't even need to work past multiplying the ones digits in each number because 9 times 0 is 0! If you do solve it you get 3,727,220, but that'd take forever to do :)

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3 years ago

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Slope = 5/2 y-intercept = 0

My name is Ann [436]

So its this answer because the y is equal to the x plus the y-intercept but the y is 0 so; y=5/2x

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3 years ago

Post-test about graphs need help

Murrr4er [49]

Answer:

O A. $y=\frac{4}{3} x-\frac{1}{3}$

Step-by-step explanation:

To find the equation of the line, we need to know the slope and the y-intercept.

so, let's start by the slope. We need two points given in the graph.

(4, 5) and (-2, -3)

Then use the Slope-Formula to identify the Slope of the line.

m = slope

m = $\frac{y2-y1}{x2-x1}$ Slope Formula

m = $\frac{-3-5}{-2-4}$ subtract the second y from the first y / second x from first x

m = $\frac{-8}{-6}$ Turn the fraction to positive because two negatives = positi-

m = $\frac{8}{6}$ Simplify

m = $\frac{4}{3}$ Final Answer

The slope of the line is $\frac{4}{3}$ now what about the y-intercept?

The y-intercept is located at the y axis.

It determines how many units the graph goes up or down depending...

Well in this case, the y-intercept is negative because it is below on the yaxis

Then we must determine the y-intercept.

so we know is negative but it isn't exactly on a point so it is formed as a fra-

then we can determine it by seeing when it hits another unit (hard explainin)

y-intercept = -1/3

Final Answer: y = $\frac{4}{3} x-\frac{1}{3}$

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3 years ago

Which equation has a graph that is a parabola with a vertex at (–1, –1)?

Artist 52 [7]

Answer:

$y=(x+1)^2-1$

which agrees with the last option listed.

Step-by-step explanation:

We use the vertex form of a parabola:

$y-y_v=a(x-x_v)^2$

which with the information we have becomes:

$y-y_v=a(x-x_v)^2\\y-(-1)_v=a(x-(-1))^2\\y=a(x+1)^2-1$

Therefore the equation that corresponds to such vertex (-1, -1) is the last one listed among your given answer options.

$y=(x+1)^2-1$

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3 years ago

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