Question

Which equation has a graph that is a parabola with a vertex at (–1, –1)?

Answer 1

Answer:

$y=(x+1)^2-1$

which agrees with the last option listed.

Step-by-step explanation:

We use the vertex form of a parabola:

$y-y_v=a(x-x_v)^2$

which with the information we have becomes:

$y-y_v=a(x-x_v)^2\\y-(-1)_v=a(x-(-1))^2\\y=a(x+1)^2-1$

Therefore the equation that corresponds to such vertex (-1, -1) is the last one listed among your given answer options.

$y=(x+1)^2-1$

Answer 2

Answer:

D

Step-by-step explanation: