Simplifying
b2 + 12b + 35 = 0
Reorder the terms:
35 + 12b + b2 = 0
Solving
35 + 12b + b2 = 0
Solving for variable 'b'.
Factor a trinomial.
(7 + b)(5 + b) = 0
Subproblem 1
Set the factor '(7 + b)' equal to zero and attempt to solve:
Simplifying
7 + b = 0
Solving
7 + b = 0
Move all terms containing b to the left, all other terms to the right.
Add '-7' to each side of the equation.
7 + -7 + b = 0 + -7
Combine like terms: 7 + -7 = 0
0 + b = 0 + -7
b = 0 + -7
Combine like terms: 0 + -7 = -7
b = -7
<span>( -26•7y6x) thats the answer i hope its right im positive it is</span>
= (7u³ + 8u² + 7) + (8u³ - 3u + 7)
Operate like terms together:
= 7u³ + 8u³ + 8u² - 3u + 7 + 7
= 15u³ + 8u² - 3u + 14
In short, Your Answer would be: 15u³ + 8u² - 3u + 14
Hope this helps!
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to
