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Paladinen [302]
3 years ago
5

The side of a square is 12 feet. What is the area of the square?

Mathematics
1 answer:
saul85 [17]3 years ago
6 0
Area of the square = Length x Length

Area of the square = 12 x 12 
Area of the square = 144 sq ft (Answer D)



---TF---
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Xavier runs 0.75 miles each day .How far has he won at the end of 6 days?
Elanso [62]

Answer:

4.5 miles

Step-by-step explanation:

You times .75 and 6 and you should get 4.5 miles

6 0
3 years ago
Read 2 more answers
A boy makes a cuboid of plasticine of sides 5cm, 2cm, 5cm. How manny such cuboids will he need to form a cube?
ruslelena [56]

Answer:

Step-by-step explanation:

L.C.M. of 5,2=10

so it should be  of dimensions 10×10×10

it should have 5 cuboids in first row.

then it will make a cuboid 5×10×5

5 cuboids in the second row on top of first row .

Then it will make 5×10×10 cuboid

To make 10×10×10

double the cuboids  to make the length=10 and height=10..

so in all 20 cuboids are needed.

2 rows of 5 cuboids on the floor and 2 rows of 5 cuboids on the top.

in all 10 cuboids of  dimensions 5×2×5

so 9 more cuboids are needed to make a c

3 0
3 years ago
QUESTION
Lorico [155]
1. For this item we just refer to the prompt to know the conjectures of Ernest and Denise. According to Ernest, they should swim 1 kilometer on the first week then add 0.25km every week while Denise believes that they should swim 1 kilometer on the first week then add 0.5km every week.

2. Yes, these distances make an arithmetic sequence. It's because an arithmetic sequence is defined as a group of increasing or decreasing numbers where the difference between any two consecutive numbers is constant. This just means that every number has the same interval. In the case of their schedule, this is true.

3. For this item we just follow the descriptions of Ernest's and Denise's schedule in item number 1. For Ernest, we just keep adding 0.25 from 1 kilometer until we added it thrice. For Denise, we also keep adding a number thrice but this time it's 0.5 instead of 0.25.

Ernest's Schedule: 1, 1.25, 1.5, 1.75
Denise's Schedule: 1, 1.5, 2, 2.5

4. Here we are asked to determine a formula that will describe the schedules of Ernest and Denise. In the given formula a_{n}= a_{n-1}+d, a_{n} refers to the next term in the sequence, a_{n-1} refers to the previous term, while d refers to the common difference. In the recursive formula all we need is to insert the value of d to the equations.

Ernest: a_{n}= a_{n-1}+0.25
Denise: a_{n}= a_{n-1}+0.5

5. For this item we basically do the same thing but this time we are given another formula. Our formula is in the form a_{n}= a_{1}+(n-1)d where a_{n} is still the nth term of the sequence, a_{1} is the very first time, n is the number of terms, and d is the common difference. 

Ernest: a_{n}= 1.0+0.25(n-1)
Denise: a_{n}= 1.0+0.5(n-1)

6. In this item we will just basically substitute numbers to one of the equations that we've set up in item #5. For this we need Ernest's explicit formula first. To know how far they will be swimming on week 10, the number of elements (n) must be 10.

a_{10}= 1.0+0.25(10-1)
a_{10}= 1.0+0.25(9)
a_{10}= 1.0+2.25
a_{10}= 3.25

7. Here, we just do the same thing as item #6 but this time we will consider Denise's explicit formula. Since we are also asked how far the students will be swimming on week 10, the number of elements would also be 10 and this would also be our value for n.

a_{10}= 1.0+0.5(10-1)
a_{10}= 1.0+0.5(9)
a_{10}= 1.0+4.5
a_{10}= 5.5

8. The answer for this question is obvious. You would just need to look at the 10th element in Ernest's and Denise's sequences and tell whose schedule had more than or equal to 5 as an answer. Following Ernest's schedule, you will just get 3.5 kilometers on the 10th week so it's definitely a no. Denise's schedule, on the other hand, would get you to 5.5 kilometers on week 10 so her training schedule should be followed.
7 0
3 years ago
David's money is three times Siti's money. Farid has RM 150 less than Siti. The total amount of their money is RM 2 000. How muc
mart [117]

Answer:

Siti's money = RM 430

David = RM 1,290

Farid = RM 280

Step-by-step explanation:

Let

Siti's money = x

David = 3x

Farid = x - 150

Total of their money = RM 2 000

x + 3x + (x - 150) = 2000

4x + x - 150 = 2000

5x = 2000 + 150

5x = 2,150

x = 2,150/5

x = RM 430

Siti's money = x

= RM 430

David = 3x

= 3(430)

= RM 1,290

Farid = x - 150

= 430 - 150

= RM 280

3 0
2 years ago
How do you solve this<br> I know the answer is x<br> But I want to know how you get to there
Vesnalui [34]

Answer:

x

Step-by-step explanation:

(–3÷(–3/(x–2)))+2

=((–3×(x–2))÷(–3))+2

=(1×(x–2)÷1)+2

=(x–2)+2

=x

5 0
3 years ago
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