Answer:
The number of students who have a test score in the interval 71-80 is <u>13</u>.
Step-by-step explanation:
Given:
The frequency chart which show the cumulative numbers of students test scores.
Now, to find the number of students who score in the interval 71-80, we will look in the frequency chart. In the chart score range of 65-80 the cumulative number of students are 13. As the 71 to 80 comes in between the score range 65-80 and there are 13 students who scored in this range.
Therefore, the number of students who have a test score in the interval 71-80 is 13.
Answer:
I think it would be 20%.
Step-by-step explanation:
$5 was taken off the original price, which is about 1/5 of $24.99. So, since 1/5 as a percent is 20%, I think the answer would be 20%.
Answer:
a) How many loops does this pattern exhibit = 3Loops
b) What is the fundamental frequency of vibration of the wire = 50Hz
c) how many loops arepresent in the new pattern = 1 Loop
Step-by-step explanation:
The concept of general wave equation is applied and then compared to the equation given in the question to determine the amplitude A, and angular frequency w as shown in the attached file.
Kent can paint the room 1/5
luannda can paint the room 1/3
(3+5) (5*3) = 8/15 or 0.53 th of the room together but just for kent would be 1/5
59064 , since i multiplied them on a calculator
