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Nadusha1986 [10]
2 years ago
7

Glossaries are usually located at the front of a text or document

Advanced Placement (AP)
2 answers:
Nutka1998 [239]2 years ago
5 0

Answer:

false

Explanation:

Vikentia [17]2 years ago
3 0
Normally a glossary would be in the back of a book. Think of a textbook, there's normally a glossary in the back of the book.
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In “Bleeding Kansas” in the mid-1850’s, _________ was/were identified with the proslavery element, and ______ was/were associate
inna [77]
The Lecompton Constitution; the New England Immigrant Aid Society < please give me a ❤️
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2 years ago
1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The
Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt

Evaluate using a calculator:

= 899.97 \approx \boxed{900\text{ people}}

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt

We can evaluate using a calculator (math-9 on T1-84):


\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt

= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}

c.

If:
P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt

Then:

\frac{dP}{dt}  = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt  = S(t) - R(t)

Evaluate at t = 20:


S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669

S(20) - R(20) = 87.844 - 108.669 = -20.823

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0
2 years ago
Using scientific terms. How plants turn sunlight into energy? Make sure to refer to a chemical equaltion photosynthesis discussi
schepotkina [342]

Answer:

Explanation:

Plants use energy from sunlight to turn water and carbon dioxide into an energy-rich sugar called glucose.this process is called photosynthesis takes place inside capsules in the leaf cells, called chloroplast. 6CO2 + 6H2O → C6H12O6 + 6O2, reactants are= Carbon dioxide,water,light energy products=Glucose and oxygen

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2 years ago
Negative impact of social media
ikadub [295]
More people compare themselves to other's "highlight reels," there's less face to face interaction, and more time spent on social media means less time for ther activities.
8 0
2 years ago
1) Calcula la diagonales de un poligono n lados. Heptágono: 2 puntos
ahrayia [7]

Answer:

El número de diagonales de un polígono de n lados se calcula mediante la siguiente fórmula:

d = \frac{n\cdot (n-3)}{2} (1)

Donde:

d - Cantidad de diagonales del polígono.

n - Cantidad de lados del polígono.

Bajo esta fórmula, tenemos los siguientes resultados:

a) El heptágono tiene 14 diagonales.

b) El octágono tiene 20 diagonales.

c) El eneágono tiene 27 diagonales.

d) El decágono tiene 35 diagonales.

e) El pentadecágono tiene 90 diagonales.

Explanation:

La cantidad de diagonales de un polígono se puede determinar mediante la siguiente ecuación:

d = \frac{n\cdot (n-3)}{2} (1)

Donde:

d - Cantidad de diagonales del polígono.

n - Cantidad de lados del polígono.

A continuación, calculamos la cantidad de diagonales de los siguientes polígonos:

Heptágono (n = 7)

d = \frac{7\cdot (7-3)}{2}

d = 14

El heptágono tiene 14 diagonales.

Octágono (n = 8)

d = \frac{8\cdot (8-3)}{2}

d = 20

El octágono tiene 20 diagonales.

Eneágono (n = 9)

d = \frac{9\cdot (9-3)}{2}

d = 27

El eneágono tiene 27 diagonales.

Decágono (n = 10)

d = \frac{10\cdot (10-3)}{2}

d = 35

El decágono tiene 35 diagonales.

Pentadecágono (n = 15)

d = \frac{15\cdot (15-3)}{2}

d = 90

El pentadecágono tiene 90 diagonales.

8 0
2 years ago
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