All categories

4 years ago

Simplify each expression 17x + 4 - 3x

Mathematics

1 answer:

Liono4ka [1.6K]4 years ago

3 0

Answer:

14x+4

Step-by-step explanation:

17x-3x=14x

You might be interested in

Easy Buy Company gave out 7 DVD's to each of their employees as gifts. There were

givi [52]

Easy Buy Company gave out 224 DVD’s

7 0

4 years ago

Read 2 more answers

What is the slope of a line that is perpendicular to the line y=8x-12

Sunny_sXe [5.5K]

Hello there!

Perpendicular lines have slopes that are opposite reciprocals. It means that if we have 8, then its opposite reciprocal would be -1/8.

Hope this helps!

~Just an emotional teen who listens to her favorite song "Try Everything"

$SilentNature :)$

8 0

3 years ago

Free 50 points for the first two answer and ask me if you want brainliest!!<br>HAVE A NICE DAY

Mashcka [7]

Answer:

can i have brainliest plz and thx so much have a great dayyyyy :)

Step-by-step explanation:

hop this helps :)

3 0

3 years ago

Read 2 more answers

Amy and Sarah are twins. They have a younger brother who is 3 years younger.

Shkiper50 [21]

Answer: no, because you are subtracting the 3 rather than adding

Step-by-step explanation:

twins= x + x

brother= x-3

equation =2x + (x-3)

4 0

3 years ago

Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b

Elenna [48]

Answer:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Step-by-step explanation:

We want to verify the identity:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }$

Collect LCM

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }$

We simplify the RHS to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}$

We rationalize to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}$

We expand to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}$

Factor negative one in the denominator:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}$

Apply the Pythagoras Property to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}$

Simplify to get:

$\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}$

$\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}$

Divide both the numerator and denominator by sin x

$\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}$

This finally gives:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

8 0

3 years ago