Answer:
46 MI
Step-by-step explanation:
5:10
8:15
X:60
Y:30
30+16
46
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
The answer is $2.52.
Step-by-step explanation:
56 x .045= $2.52
Answer: 58 14ths
Step-by-step explanation:
multiply 14 by 4 to get 56 14ths, then add the 2
Answer:
<em>615.44m²</em>
Step-by-step explanation:
The base of the silo is a circle
Rea of the base of the silo = πr²
r is the radius of the silo
Given
radius r = 14m
Area of the base of the silo = π(14)²
Area of the base of the silo = 3.14(196)
Area of the base of the silo = 615.44
<em>Hence the area of the base of the silo is 615.44m²</em>
