Answer:
def typeHistogram(it,n):
d = dict()
for i in it:
n -=1
if n>=0:
if str(type(i).__name__) not in d.keys():
d.setdefault(type(i).__name__,1)
else:
d[str(type(i).__name__)] += 1
else:
break
return list(d.items())
it = iter([1,2,'a','b','c',4,5])
print(typeHistogram(it,7))
Explanation:
- Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
- Initialize an empty dictionary and loop through the iterator "it".
- Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
- At the end return the list of items.
- Finally initialize the iterator and display the histogram by calling the typeHistogram.
Answer:
=b2 b3-b4 or something close to that, I hope this helps ^^
Explanation:
Exhaust Gas Recirculation (EGR) for NOx control
<span>Positive Crankcase Ventilation (PCV) for HC emission control </span>
Evaporative Emissions Control(EVAP)
<span>Catalytic Converter for HC and NOx control</span>
Answer:
Check the explanation
Explanation:
223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.
The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000
Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)
So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26
Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)
and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25
Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)
So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28
Answer:
Well the background sound is the sound of course in the background and the nat sound is the curremt sound
Explanation:
