The best way I can explain the elimination method is, it's a method where you either add or subtract equations in order to get rid of a variable.
Hello!
Step-by-step explanation:
Mean: 48
Median: 40
Mode: None
Range: 63
Hope this helps!
Answer:
cannot be determined
Step-by-step explanation:
We do not know if any of the angles are equal and are only given two sides.
We cannot determine if the two triangles are similar
You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

Complete the square:

And we have:

So the answer is C (the same left side of equation).
first speed --- x mph
return speed -- x+16 mph
6/x + 6/(x+16) = 1
times each term by x(x+16)
6(x+16) + 6x = x(x+16)
x^2 + 4x - 96 = 0
(x-8)(x+12) = 0
x = 8 or x is a negative
her first speed was 8 mph
her return speed was 24 mph
check:
6/8 + 6/24 = 1 , that's good!