2 years ago

PUZZLE: six wolves catch six lambs in six minutes. How many wolves will be needed to catch sixty lambs in sixty minutes?

Mathematics

1 answer:

Korolek [52]2 years ago

4 0

Six i think cause it take each wolf 6 minutes to catch a lamb so it should still be six

You might be interested in

You are creating bracelets and then selling them to your friends at a 85% markup rate. If it costs you $1.80 to create the brace

posledela

Answer:

you will add $1.53 to every bracelet you make

Step-by-step explanation:

figure out what 85 percent of 1.80 is and then add that to 1.80 for the total price

85% x 1.8 = 1.53 (markup ammount)

1.80 + 1.53 = 3.33 (total cost)

5 0

3 years ago

Karl bought 3 and 1/2 gallons of milk that cost $2.70 per gallon.

Vesna [10]

Answer:

9.45

Step-by-step explanation:

3.5 x 2.7 = 9.45

5 0

2 years ago

Read 2 more answers

Henri's bill at a restaurant is $19.62. He wants to leave a tip of 20%, or , of the bill. To find the exact amount of the tip, h

ratelena [41]

Answer:

0.2

Step-by-step explanation:

19.62*0.2

Multiply by 0.2

Hope this helps plz hit the crown :D

3 0

2 years ago

ricardo lost 6 balls while playing golf.he bought 12 golf balls,then he lost 4 on the course to day.now he has 18 balls.how many

adell [148]

16 golf balls. Hope this helps

7 0

2 years ago

Read 2 more answers

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that $P(A \cup B) = 0.95$

80% passed in mathematics 75% passed in english

This means that $P(A) = 0.8, P(B) = 0.75$

Proportion who passed in both:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Considering the values we have for this problem

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6$

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

$0.6t = 3000$

$t = \frac{3000}{0.6}$

$t = 5000$

5000 students appeared in the examination.

4 0

2 years ago