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garri49 [273]
2 years ago
12

Can someone please help me ?

Mathematics
2 answers:
IRINA_888 [86]2 years ago
8 0
Sure, What's up! What kinda help do you need. Give me subjects grade level.
Mrrafil [7]2 years ago
7 0
-256 would be my guess
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First solve the length of side BC, CD, EF and FA   Since BC = CD = sqrt( 10^2 + 10^2) BC = CD = 14.1421  
FA = EF = sqrt(10^2 + 20^2) = 23.3607  
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607 = 93

The area is made up be triangle FAE, rectangle ABDE and triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
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3 years ago
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In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria
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Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

P(t)=ae^{rt}\\\\where\ t\ is\  the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start

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P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)

After another 2 hours (4 hours), the population is 1 million:

P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844

Put r = 4.844 in equation 1

62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844

P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844

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3 years ago
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19 toy cars arent in the box

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What is the domain
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<h3>Answer: Give the domain and the range of each quadratic function whose graph is described. The vertex is (−1,−2)(−1,−2) and the parabola opens up.</h3>

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2 years ago
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How many solutions does -3(2x + 6) = -6x - 18 have
viktelen [127]

Answer: 0=0 The input is an identity or it is true for all values

-3(2x+6)=-6x-18

(-3*2x)+(-3*6)=-6x-18

-6x+-18=-6x-18

0=0

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2 years ago
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