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oee [108]
3 years ago
5

Can someone explain too??

Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

5\sqrt{2}

Step-by-step explanation:

prime factorising 50 inside root,

\sqrt{50}=\sqrt{5*5*2}

      5*5 is a perfect square

    So root of 5*5(or 25) is 5.

Hence 5 comes outside and 2 remains in bracket.

=5\sqrt{2}

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What is the perimeter of the triangle (4,1) (2,5) (1,-1)
Naya [18.7K]

the perimeter of the triangle=14.38

The coordinates of the triangle (4,1),(2,5),(1,-1);

In geometry, the perimeter of a shape is defined as the total length of its boundary.

The perimeter of the triangle is the sum of all the sides of the triangle =a+b+c (assuming a,b, and c are the sides of the triangle)

By using the distances formula find the length of the sides of the triangle:√[(x₂ - x₁)² + (y₂ - y₁)²],

where (x₁,y₁),(x₂,y₂) are the coordinates ,

a=√[(4 - 2)² + (1- 5)²] = \sqrt 20=4.7

b=√[(2 -1)² + (5 -(-1))²]=\sqrt37=6.08

c=√[(1 -4)² + ((-1)-1)²]=\sqrt13=3.60

the perimeter of the triangle=a+b+c=4.7+6.08+3.60=14.38

hence ,perimeter of the triangle=14.38

Learn more about perimeter of triangle:

brainly.com/question/23935199

3 0
1 year ago
You rearrange your bedroom. Tell whether each move is an example of
mash [69]

Answer:

translation,reflection,

Step-by-step explanation:

because you move thing in different direction

4 0
3 years ago
A light bulb filament is one-hundredth of an inch thick, with an allowable error of 2 percent. What is the least allowable thick
Andreyy89

Answer:

0.00998 Inches

Step-by-step explanation:

Thickness of the light bulb filament = 0.01 Inch

Allowable error = 2%.

2% of 0.01 = 0.02 X 0.01 =0.0002 Inch

Therefore, the allowable thickness of the bulb filament

=0.01 \pm 0.0002 $ Inches

We can then calculate the least allowable thickness of the filament as:

=0.01 - 0.0002 \\=0.00998$ Inches

The least allowable thickness of the filament is 0.00998 Inches.

3 0
3 years ago
What is 2 x + 2y equals negative 6 coordinate
Andrews [41]
This is solved for all values of
y = -x-3. (Assuming you meant that 2x+2y=-6).
3 0
3 years ago
Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2
Dmitry_Shevchenko [17]

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

45(a^(4))(b^(10))

3 0
3 years ago
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