That would be rolling a 1 and a 2 .
so possibilities are 1 on first die and 2 on the second die
OR 2 on first die and 1 on the second.
Both of these have a probability of 1/6 * 1/6 = 1/36
so required probability = 1/36 + 1/36 = 2/36 = 1/18
Answer:
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Answer:
21
Step-by-step explanation:
21
Answer:
It's A, Because it makes the most sense in this algebra question.
Step-by-step explanation:
Have a great day!
Stay safe and healthy!
Happy holiday seasons!