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alexdok [17]
3 years ago
9

How are numerical expressions and algebraic expressions different

Mathematics
1 answer:
lozanna [386]3 years ago
7 0
Numerical expressions use numbers and algebraic expressions use variables.
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The product of twice a number and six is the same as the difference of eleven times the number and 5/6. Find the number.
laila [671]

Answer:

9.16666

Step-by-step explanation:

now answer my question or ask a freind

5 0
4 years ago
what are the mean variacne and standard deviatioon of the values? round to the nerates tenth. 11,11,3,1,11
alexdok [17]

Answer:

Mean = 8

Variance = 22

Standard deviation = 4.6904

Step-by-step explanation:

To find out Mean the formula is : total sum of data set / number of values

(11 + 11 + 3 + 1 + 11 + 11) / 6 = 48 / 6 = 8

Mean = 8

Now for variance we will form a table

x                  11     11     3      1      11      11

(x - Mean)    3     3    -5     -7      3      3  

(x - Mean)²   9     9    25    49    9      9

Now we the formula of variance =

Variance = (9+9+25+49+9+9)/(6-1) = 110/5 = 22

Variance = 22

Now we know Standard deviation = √(variance)

Therefore standard deviation = √22 = 4.6904

Hope this helps!<3

4 0
2 years ago
Read 2 more answers
What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup
zhannawk [14.2K]

Answer:

- \frac{3}{4} \times  \frac{p^{8} }{q^{3} }

Step-by-step explanation:

We have to find the quotient of the following division, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}.

Now, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}

= - \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]} {Since all the terms in the expression are in product form, so we can treat them separately}

{Since we know the property of exponent as \frac{a^{b} }{a^{c} } = a^{(b - c)}}

= - \frac{3}{4} p^{8} q^{-3}

= - \frac{3}{4} \times  \frac{p^{8} }{q^{3} } (Answer)

{Since we know, a^{-b} = \frac{1}{a^{b} }}

3 0
3 years ago
Read 2 more answers
Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the
AveGali [126]

The true statement is h(2)=16.

<h3 /><h3>What is domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function. The range of a function is the set of values that the function assumes.

Given:

domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25,

Also, h(8) = 19 and h(-2) = 2,

Now,

2=h(-2)< h(2)<h(8) =19

h(8)=19≠21

h(13)> h(8) =19

h(-3)< h(-2) =2  [1 ≤ h(x) ≤ 25]

Hence, h(2)=16

Learn more about domain and range:

brainly.com/question/23199615

#SPJ1

5 0
2 years ago
Identify the phrase that cannot be described by the same absolute value as the other three. Explain your reasoning.
r-ruslan [8.4K]
The answer would probably be 18 degrees below normal because the absolute values of the rest are 8 not 18 which is the absolute value of 18 degrees below normal.
6 0
4 years ago
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