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natulia [17]
3 years ago
14

Which digit in 98.765 is in the thousandths place

Mathematics
2 answers:
Amanda [17]3 years ago
8 0
5 would be in the thousandths place because 3 spaces away from the decimal point would be the thousandths place
Neko [114]3 years ago
6 0
The thousandths place is the third digit after the decimal point.
5 is in the thousandths place since it is the third digit after the decimal.

Have an awesome day! :)
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What is the height of cone S?
balu736 [363]

Answer:

12 cm

Step-by-step explanation:

First, we find the scale factor from cone S to cone T.

ratio of volumes = (vol of T)/(vol of S) = (6144 pi cm^3)/(768 pi cm^3) = 8

The ratio of the volumes is 8:1

The scale factor, which is the ratio of linear dimensions (height, radius, etc.), is the cubic root of the ratio of the volumes.

scale factor = cubic root of 8 = 2

The height of cube T is 24 cm, so the height of cube S is 24 cm/2 = 12 cm.

4 0
3 years ago
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Which choice shows 1/4 of 8
yulyashka [42]

Answer:

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Write the equation for the quadratic function in the graph
Hoochie [10]

Answer:

{x}^{2}  - 16 = 0 \: is \: the \: equation

Step-by-step explanation:

x =  - 4 \\ or \: x = 4

(x + 4) = 0 \: or \: (x - 4) = 0 \\ (x + 4)(x - 4) = 0 \\ open \: the \: bracket

x(x - 4) + 4(x - 4) = 0

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6 0
2 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

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Answer:

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Step-by-step explanation:

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