HELP IF YOU HAVE A HEART PLEASE I'M TIMED AND RLLY STRESSED OUT

A serving of hot chocolate requires ¾ cup of milk. How many servings can Nina make with 7 ½ cups of milk? *

patriot [66]

Answer:

8 cups of hot chocolate

Step-by-step explanation:

6 0

3 years ago

Plzzz help plzzzzzzzzzzzzzz

mezya [45]

Given:

The figure of two quadrilaterals.

In $ABCD,AB=18,BC=20,CD=22,AD=24$

In $EFGH,EF=27,FG=30,GH=34, EH=36$

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

$\dfrac{AB}{EF}=\dfrac{18}{27}$

$\dfrac{AB}{EF}=\dfrac{2}{3}$

Similarly,

$\dfrac{BC}{FG}=\dfrac{20}{30}$

$\dfrac{BC}{FG}=\dfrac{2}{3}$

$\dfrac{CD}{GH}=\dfrac{22}{34}$

$\dfrac{CD}{GH}=\dfrac{11}{17}$

And,

$\dfrac{AD}{EH}=\dfrac{24}{36}$

$\dfrac{AD}{EH}=\dfrac{2}{3}$

Clearly, $\dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}$ .

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0

3 years ago

Is (–5, 0.5) a solution of this system? x – 4y = –7, 0.2x + 2y = 0 Substitute (–5, 0.5) into x – 4y = –7 to get . Substitute (–5

kaheart [24]

ANSWER:

(-5, 0.5) is the solution of given equation x – 4y = –7, 0.2x + 2y = 0.

SOLUTION:

Given, two equations are x – 4y = -7 → (1)

And 0.2x + 2y = 0 → (2)

We have to find whether (-5, 0.5) is a solution of given system or not.

For that, we have to solve the given two equations.

Before solving let us multiply equation (2) with 2 in order to get y terms cancelled. Such that, our process becomes easy.

Now equation (2) becomes

0.4x + 4y = 0 → ( 3 )

Now, add equation (1) and equation (3), we get

1.4x + 0 = -7

$x=\frac{-7}{1.4}=-5$

Now, substitute x value in (2)

0.2(-5) + 2y = 0

-1 + 2y = 0

2y = 1

y = 0.5

So, the solution for given equations is (-5, 0.5).

Hence (-5, 0.5) is the solution of given equations.

8 0

4 years ago

Read 2 more answers

What is the value of b in the equation (y^-9)^b=y^45?

nevsk [136]

Answer:

b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

Step-by-step explanation:

Solve for b:

(1/y^9)^b = y^45

Take the logarithm base 1/y^9 of both sides:

Answer: b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

5 0

4 years ago

Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it

hodyreva [135]

Answer:

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2. What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0

3 years ago