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3 years ago

What is the percent of 60 is 15

1 answer:

5 0

To find the percent of 15 out of 60, you have to divide fifteen by sixty.
Then, you multiply your answer by 100. (We do this because 100 percent is a exact amount. 100% of sixty is...well, sixty.)

15 / 60 = 0.25

Now, we can multiply 0.25 by 100:

0.25 * 100 = 25 (basically just moving the decimal two places to the right.)

Next, add a percent sign:

25%, is your answer.

15 is 25% of 60.

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] Monica Geller, head chef at Allesandro's and is looking to update the commercial equipment in her kitchen and bar that will al

liubo4ka [24]

Answer:

The maximum amount that should be spent on the upgrade is $38,298,000.

Step-by-step explanation:

Let the initial purchase be x.

The ROI = 15% of x = 0.15x

At the end of 4 years, salvage value = 10% of x = 0.1x

Current income per day = $16 × 230 = $3680

Expected income per day = $21 × 245 = $5145

Increase in income per day = $5145 - $3680 = $1465

For 4 years (assuming a year is 365 days),

Increase in income = $1465 × 365 × 4 = $2138900

Maintenance and utility cost for 4 years = 4 × $56000 = $224000

At the end of 4 years,

ROI = $2138900 + salvage value = $2138900 + 0.1x - $224000

0.15x = $1914900 + 0.1x

0.05x = $1914900

x = $38298000

5 0

3 years ago

Read 2 more answers

What does f(x-5) do to the graph

Romashka [77]

It moves five squares to the left because it is -5 so it’s decreasing

3 0

2 years ago

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

El área de un rectángulo es 675cm2, si el largo es 3 veces. ¿Cuáles son las dimensiones del rectángulo?

Gala2k [10]

The answer is 15 cm. Hope I could be of help! ; )

7 0

3 years ago

6 divided by 2 (1+2)

user100 [1]

Observe.

6/2(1+2)
6/2(3)
6/6
1

Thus, the answer is: 1

4 0

3 years ago

Read 2 more answers