What is the slope of the line through point B, perpendicular to line k?

Point C has a _____ abscissa and a _____ ordinate.

VladimirAG [237]

Answer:

i think its b but im not that sure

Step-by-step explanation:

5 0

1 year ago

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

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Area of triangle

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We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

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So:-

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

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$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

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$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

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$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

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$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]

7 0

1 year ago

I NEED HELP ASAP!! WILL GET 15 POINTS FOR THE CORRECT ANSWER!!!

Elanso [62]

All real numbers such that y is greater than 3/17 or y>3/17. Hope this helps!!!!

7 0

3 years ago

How do you make x the subject of the formula when your formula is y= abx? Please can you show me how you worked it out if you an

GrogVix [38]

If you want to solve for x you have to get x alone on one side of the equals sign. In order to do that you have to get rid of the stuff on the same side by doing the opposite operation so that it cancels. What you do on one side you do on. the other side to keep the equation true.

y= abx

a and b are being multiplied by x so divide by ab to cancel them out (ab/ab is 1).

y= abx/ab (ab cancels)

now divide the other side by ab to keep the equation true.

y/ab= x

7 0

3 years ago

Need help on these problems

kupik [55]

Simple Interest = Principal * Interest Rate * Term
Total Amount = Principal + Simple Interest

 # Principal Interest rate term Interest Total balance
 1 100.00 6% 1 6.00 106.00
 3 100.00 6% 2 12.00 112.00
 5 100.00 6% 3 18.00 118.00
 7 100.00 6% 4 24.00 124.00
 9 3,000.00 5% 3 450.00 3,450.00
10 4,000.00 6% 3 720.00 4,720.00
11 10,000.00 4% 3 1,200.00 11,200.00
13 10,000.00 6% 4 2,400.00 12,400.00
14 10,000.00 6% 5 3,000.00 13,000.00

5 0

2 years ago