Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34
a(2) = a + d = 34 + 7 = 41.
So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
Answer:
1. (3^3 + 3^2)^2 actually equals (27 + 9)^2
which is the first mistake
2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7
3. 3^7 DOES NOT EQUAL 21
Step-by-step explanation:
when you add powered numbers together, it does not multiply it, as your example:
1. (3^3 + 3^2)^2 actually equals (27 + 9)^2
which is the first mistake
2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7
3. 3^7 DOES NOT EQUAL 21
2. 89
3. 568
4. 987
5. 854
6. 797
all u do is add