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3 years ago

Help!? I don't understand

Mathematics

2 answers:

leonid [27]3 years ago

6 0

I believe the answer is 25% sorry if it's wrong.

liq [111]3 years ago

5 0

It would be 82 or 54

Because 72-18=54%
OR 100-18 would be =82

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Consider the given function and the given interval. f$x$ = (x - 7)**2 text(, ) [5 text(, ) 11] (a) Find the average value fave

Jet001 [13]

a. $f$ has an average value on [5, 11] of

$f_{\rm ave}=\displaystyle\frac1{11-5}\int_5^{11}(x-7)^2\,\mathrm dx=\frac{(x-7)^3}{18}\bigg|_5^{11}=\frac{4^3-(-2)^3}{18}=4$

b. The mean value theorem guarantees the existence of $c\in(5,11)$ such that $f(c)=f_{\rm ave}$ . This happens for

$(c-7)^2=4\implies c-7=\pm2\implies c=9\text{ or }c=5$

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4 years ago

Equation of the line that passes through the points (-3,8) and has a slope of zero

stiks02 [169]

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Step-by-step explanation:

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3 years ago

True or false<br><br> A rhombus is an isosceles trapezoid

Elina [12.6K]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

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Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

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3 years ago

HELPPPPPPPPPPPPPPPPP!!

goldfiish [28.3K]

Answer:

option 3

Step-by-step explanation:

V= πr²h

to make h the subject

h= V÷πr²

just take πr² to the other side

as it in multiplication on the left hand side, it will in division in right hand side.

hope it helps!

5 0

3 years ago