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PtichkaEL [24]
3 years ago
15

The average distance from Jupiter to the Sun is about 4 x 108 miles. The average distance from Venus to the Sun is about 8 x 107

miles. The average distance from Jupiter to the Sun is about how many times as great as the average distance from Venus to the Sun?
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0
The average distance from Jupiter to the Sun is about 2 times as great as the average of the distance from Venus to the Sun.
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please answer please!!!! Will mark brainliest for complete answer. -the first photo is to calculate the area. Just question numb
cricket20 [7]
Triangle:
Area = 1/2*b*h
= (1/2)*3*4
= 3*2
= 6 m^2


7a.
1cm^3
Or, 1cm * 1cm * 1cm
Or, 10mm * 10 mm * 10 mm
Or, 1000 mm^3

7b.i)
10 cm^3
Or, 10cm * 1cm* 1cm
Or, 100mm * 10mm * 10mm
Or, 10000 mm^3

8.)
Volume = 50 cm^3
Base area= 5 cm^2
Now,
Volume = area * height
Or, 50 = 5 * height
Or, height = 50/5
Or, height = 10 cm

Plz mark this as the brainiest. :)
5 0
3 years ago
Heather invested $8000 in a 4- year certificate of deposit (CD) that pays 4.1 interest compound annually. What is the value of t
aliya0001 [1]
8000(1.041)x^{4}=9394.91
6 0
3 years ago
The ordered pairs (1, 1), (2, 8), (3, 27), (4, 64), and (5, 125) represent a function. What is a rule that represents this funct
Zarrin [17]
The functions would be:

D. y=x³

We can check it out.

(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
8 0
3 years ago
Question Help
Sergeeva-Olga [200]

Answer:

if u divide it then slop  it u will get your answer

3 0
3 years ago
(x+16)²=12 plz help me and show work
Readme [11.4K]

Answer:

The answer is x=-16 ±2\sqrt{3} in exact form or x=-12.535898, x=-19.464102 in decimal form.

Step-by-step explanation:

To solve this problem, start by moving all terms to the left side of the equation and simplify. Simplify the equation by subtracting 12 from both sides of the equation and squaring x+16, which will look like x^{2} +32x+256-12=0. Next, simplify the equation again, which will look like x^{2} +32x+244=0.

Then, use the quadratic formula to find the solutions. The quadratic formula looks like\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}.

For this problem, the quadratic variables are as follows:

a=1

b=32

c=244

The next step is to substitute the values a=1, b=32, and c=244 into the quadratic formula and solve. The quadratic formula will look like \frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}. To simplify the equation, start by simplifying the numerator, which will look like x=\frac{-32(+-)4\sqrt{3} }{2*1}. Then, multiply 2 by 1 and simplify the equation, which will look like x=-16(+-)2\sqrt{3}. The final answer is x=-16 ±2\sqrt{3} in exact form. In decimal form, the final answer is x=-12.535898, x=-19.464102.  

6 0
3 years ago
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