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MatroZZZ [7]
3 years ago
5

The polygons in each pair are similar. find the missing side length​

Mathematics
1 answer:
pochemuha3 years ago
6 0

If both are similar ratio of sides will be same

\\ \sf\longmapsto  \frac{x}{25}  =  \frac{7}{5}  \\ \\ \sf\longmapsto 5x = 7 \times 25 \\ \\ \sf\longmapsto 5x = 175 \\ \\ \sf\longmapsto x =  \frac{175}{5}  \\ \\ \sf\longmapsto x = 35

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Please Help! Thanks!
svetlana [45]

Answer:

C, 20 units

Step-by-step explanation:

We see that both angles QRS and QTR are 90 degrees. In addition, angles SQR and RQT are equivalent (because they're both angle Q).

By AA Similarity, we know that triangle QTR is similar to triangle QRS.

With this similarity in mind, we can look at the ratios of corresponding lengths to set up a proportion. QR from triangle QTR is the hypotenuse, and it corresponds to hypotenuse QS from triangle QRS. So, we can write the ratio x/(9 + 16) = x/25.

Now, we see that long leg QT of triangle QTR corresponds to long leg QR of triangle QRS. So, another ratio we can write is: 16/x.

Finally, we set these two ratios equal to each other:

\frac{x}{25} =\frac{16}{x}

Cross-multiplying, we get: x^{2} =16*25=400.

Thus, x = \sqrt{400} =20. The answer is C, 20 units.

Hope this helps!

4 0
3 years ago
Read 2 more answers
What is the cube root of 27a^12
tino4ka555 [31]

ANSWER

3{a}^{4 }

EXPLANATION

The cube root of

27 {a}^{12}

is

\sqrt[3]{27 {a}^{12} }

This is the same as:

(27 {a}^{12} )^{ \frac{1}{3} }

( {3}^{3} ({a}^{4})^{3}  )^{ \frac{1}{3} }

=  (3{a}^{4} )^{3 \times  \frac{1}{3} }

= 3{a}^{4 }

6 0
3 years ago
What is the answer for -8=s+6
9966 [12]

Answer:

s=-14

Step-by-step explanation:

-8 = s+6       Given

-14 = s          Subtract 6 from both sides

7 0
3 years ago
Whats the answer for this <br> 4b²+20b+25
WITCHER [35]
4b²+20b+25=0

Divide everything by 4 

b²+5b+ 6.25=0 

use the quadratic formula 
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2

7 0
3 years ago
Write a quadratic function for each graph described.
user100 [1]

Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

40=a(6)(\frac{10}{3})

40=20a\\a=2

substitute

y=2(x+1)(x-\frac{5}{3})

apply distributive property

y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}

see the attached figure to better understand the problem

6 0
3 years ago
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