Standard for ola (y + 3)2 = -12(x - 2), iden 1. D n111

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

5 0

Answer:

See below

Step-by-step explanation:

Your question is a bit unclear, so I'm going to assume you want the value of y or x:

(y+3)^2=-12(x-2)

-(y+3)^2/12=x-2

-(y+3)^2/12+2=x

(y+3)^2=-12(x-2)

y+3=sqrt(-12x+24)

y=sqrt(-12x+24)-3

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Work Shown:

$\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\$