Center of rhombus bisects 90°.
Sum of angles in triangle = 180°
x + x + 14 + 90 = 180
2x + 104 = 180
2 (x + 52) = 180
x = (180 ÷ 2) - 52
x = 90 - 52
x = 38°
Step-by-step explanation:


Here, the Taylor approximation for a square root was applied, and O(x) stands for all negligible terms of Taylor's sum with respect to variable x.
So, 
b. For an increase of 2%, that is:


Answer:
n=9
Step-by-step explanation:
because 3 times 9 =27 plus 17 =44
Answer:
c
Step-by-step explanation:
she pays a one-time fee of 50, and 15$ per month
Answer:
Distance between the points = 10 units
Step-by-step explanation:
Given points:
(0,-2) and (-8,-8)
To find the distance between the two points.
Solution:
Applying distance formula to find the distance between the points.
For points
and
the distance is given as:

Plugging in the given points in the formula.






Since distance is always positive. So
units.