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Tomtit [17]
3 years ago
14

Name two ways you can figure out an area of a composite figure.

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0

Answer: they contain valuable items and are very interesting

Step-by-step explanation:

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Create a real-world situational problem to represent the given equation or inequality.
Gala2k [10]

Answer:

wheres the rest of it

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ON THIS MATH PROBLEM
gogolik [260]

Answer:   y = -10 sin (πx) + 4

<u>Step-by-step explanation:</u>

y = A sin (Bx - C) + D

  • Amplitude: A
  • Period = 2π/B    --->    B = 2π/Period
  • Phase Shift = C/B  --> C = B · Phase Shift
  • D: midline, vertical shift

Given:

  • A = 10
  • B = 2π/2 = π
  • C = B · 0 = 0
  • D = 4
  • reflection over x- axis

Equation:

    y = -10 sin (πx - 0) + 4

5 0
3 years ago
Two similar cones have volume of 4 m and 108 m respectively. If the large one has surface area 54 m, find the surface area of th
trasher [3.6K]

 

\displaystyle\bf\\Explanations:\\\\The~similarity~ratio~of~two~similar~cones=k\\\\k=is~the~ratio~between~2~corresponding~lengths\\\\k=\frac{R_1}{R_2}=\frac{h_1}{h_2}\\\\The~ratio~between~2~corresponding~areas~of~similar~cones=k^2\\\\\frac{Area~1}{Area~2}=k^2\\\\The~ratio~between~the~volumes~of~the~2~similar~cones=k^3\\\\\frac{Volume~1}{Volume~2}=k^3

.

\displaystyle\bf\\Solving:\\\\Volume1=108~m^3\\\\Volume2=4m^3\\\\k^3=\frac{108}{4}\\\\k^3=27~~\Big|\sqrt{~}\\\\k=\sqrt[\b3]{27}\\\\k=3\\\\Area1=54~m^2\\\\\frac{Area~1}{Area~2}=k^2\\\\\frac{54}{Area~2}=3^2\\\\\frac{54}{Area~2}=9\\\\Area2=\frac{54}{9}\\\\\boxed{\bf Area2=6 m^2}

 

4 0
3 years ago
Add (13a + 5b) + (a + 5b - 3)
Anni [7]
<span>(13a + 5b) + (a + 5b - 3)
</span><span>
= 13a + 5b + a + 5b - 3
 
= 14a + 10b - 3 </span>
5 0
3 years ago
Find all possible values of k so that x^2 + kx - 32 can be factored.
daser333 [38]

Answer:

Step-by-step explanation:

The posssible factors are

x^2 + 4x - 32

(x+8)(x-4)

x^2+ 14x - 32

(x+16)(x-2)

(x+32)(x-1)

x^2+31x-32

8 0
3 years ago
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