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4 years ago

ANSWER IN ONE MINUTE AND YOU WILL BE THE BRAINLIEST!

Mathematics

2 answers:

Alborosie4 years ago

8 0

Answer:

Step-by-step explanation:

ludmilkaskok [199]4 years ago

4 0

A because you would have to turn the mixed
fraction into a improper fraction which would turn it into 13/4 not 4/13 then multiply by 5/1.

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Carol earns 50% more than william how much larger her income than his

stiks02 [169]

Answer:

To answer this question, we would need William's income

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Mc010-1.jpgx – 4 = –2

Katen [24]

The picture isn't loading so i'll answer based on what is shown.

If x-4=-2, then x is 2.

3 0

4 years ago

At what angle of evaluation is this person looking up at the church?

sesenic [268]

Answer:

It looks like he is looking at a 30 or 45 degree angle, but I am 99.99% sure that it is 30 percent.

Step-by-step explanation:

6 0

3 years ago

P(x < 21 | μ = 23 and σ = 3) enter the probability of fewer than 21 outcomes if the mean is 23 and the standard deviation is

Shkiper50 [21]

Answer:

(a) The value of P (X < 21 | μ = 23 and σ = 3) is 0.2514.

(b) The value of P (X ≥ 66 | μ = 50 and σ = 9) is 0.0427.

(d) The value of P (17 < X < 24 | μ = 21 and σ = 3) is 0.7495.

(e) The value of P (X ≥ 95 | μ = 80 and σ = 1.82) is 0.

Step-by-step explanation:

The random variable X is Normally distributed.

(a)

The mean and standard deviation are:

$\mu=23\\\sigma=3$

Compute the value of P (X < 21) as follows:

$P(X$

$=P(Z$

Thus, the value of P (X < 21 | μ = 23 and σ = 3) is 0.2514.

(b)

The mean and standard deviation are:

$\mu=50\\\sigma=9$

Compute the value of P (X ≥ 66) as follows:

Use continuity correction.

P (X ≥ 66) = P (X > 66 - 0.5)

= P (X > 65.5)

$=P(\frac{X-\mu}{\sigma}>\frac{65.5-50}{9})$

$=P(Z>1.72)\\=1-P(Z$

Thus, the value of P (X ≥ 66 | μ = 50 and σ = 9) is 0.0427.

(c)

The mean and standard deviation are:

$\mu=50\\\sigma=5$

Compute the value of P (X > 47) as follows:

$P(X>47)=P(\frac{X-\mu}{\sigma}>\frac{47-50}{5})$

$=P(Z>-0.60)\\=P(Z$

Thus, the value of P (X > 47 | μ = 50 and σ = 5) is 0.7258.

(d)

The mean and standard deviation are:

$\mu=21\\\sigma=3$

Compute the value of P (17 < X < 24) as follows:

$P(17$

$=P(-1.33$

Thus, the value of P (17 < X < 24 | μ = 21 and σ = 3) is 0.7495.

(e)

The mean and standard deviation are:

$\mu=80\\\sigma=1.82$

Compute the value of P (X ≥ 95) as follows:

Use continuity correction:

P (X ≥ 95) = P (X > 95 - 0.5)

= P (X > 94.5)

$=P(\frac{X-\mu}{\sigma}>\frac{94.5-80}{1.82})$

$=P(Z>7.97)\\=1-P(Z$

Thus, the value of P (X ≥ 95 | μ = 80 and σ = 1.82) is 0.

8 0

3 years ago

A species of animal is discovered on an island. Suppose that the population size P(t) of the species can be modeled by the follo

Ilya [14]

Answer:

The initial population is 200

The population after 10 years is 687

Step-by-step explanation:

Given

$P(t) =\frac{800}{1+ 3e^{-0.29t.}}$

Solving (a): The initial population

Here:

$t = 0$

Substitute 0 for t in P(t)

$P(0) =\frac{800}{1+ 3e^{-0.29*0}}$

$P(0) =\frac{800}{1+ 3e^{0}}$

$P(0) =\frac{800}{1+ 3*1}$

$P(0) =\frac{800}{1+ 3}$

$P(0) =\frac{800}{4}$

$P(0) =200$

The initial population is 200

Solving (b): Population after 10 years.

Here

$t = 10$

Substitute 10 for t in P(t)

$P(10) =\frac{800}{1+ 3e^{-0.29*10}}$

$P(10) =\frac{800}{1+ 3e^{-2.9}}$

$P(10) =\frac{800}{1+ 3*0.055}$

$P(10) =\frac{800}{1+ 0.165}$

$P(10) =\frac{800}{1.165}$

$P(10) =687$ -- approximated.

The population after 10 years is 687

4 0

3 years ago