What is 0.125 0.4 0.62 1.05 0.05 from least to greatest

Leviafan [203]

The solution to the composite function f(g(x)) is 9x² - 78x + 165.

<h3>What is composite function?</h3>

A composite function is generally a function that is written inside another function.

Function composition is an operation that takes two functions f and g, and produces a function h = g ∘ f such that h(x) = g.

From the given composite function, the solution is determined as follows;

to solve for f(g(x)), we use the following methods.

f(x) = x² + 2x - 3, g(x) = 3x - 14

f(g(x)) = (3x - 14)² + 2(3x - 14) - 3

= 9x² - 84x + 196 + 6x - 28 - 3

= 9x² - 78x + 165

Thus, the solution to the composite function f(g(x)) is 9x² - 78x + 165.

Learn more about composite function here: brainly.com/question/10687170

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The complete question is below:

F(x) =x2+2x-3 g(x)=3x-14, find f(g(x))

8 0

1 year ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago

You and three friends go out to eat and decide to split the bill evenly. The food you order comes to a total of $48. If you leav

zloy xaker [14]

Answer:

11.64

Step-by-step explanation:

100%-> 48

15%-> 7.20

6.25%-> 3

48+7.20+3=58.20

58.20÷5=11.64

4 0

3 years ago

2+2 plz help i think it's 22

Kryger [21]

Answer: 4!!!!!!!!!!! Or is it 9?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Amy wrote a check for $32 to pay her monthly electricity bill, but when balancing her checkbook, she accidentally recorded it as

ElenaW [278]

Her check register will have a surplus of 64 dollars compared to her actual balance.
example
100 +32 = 132 (incorrect)
100 -32 = 68 (correct)
132 -68 = 64 surplus

7 0

2 years ago

Read 2 more answers