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xenn [34]
3 years ago
11

How to compare 2 quantites so that the second quantity has a value of 1 without using a diagram

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0
I am not sure but i think you were to say this:(1st quality)x=(      )(2nd quality)
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What is the term, coefficient, constant, and factor of 1/2(base1 + base2)h? (Formula used to find area of trapezoid)
vovangra [49]

Answer:

i. Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

ii. Coefficient = \frac{1}{2}

iii. Constant = \frac{1}{2}

iv. Factor = \frac{h}{2}

Step-by-step explanation:

A trapezoid is a quadrilateral which has its base parallel to the opposite side. It's area can be determined by;

Area of trapezium = \frac{1}{2} (b_{1} + b_{2})h

Where b_{1} is the measure of length of its fist base,  b_{2} is the measure of its second base and h is its height.

Considering the given question,

Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

Coefficient = \frac{1}{2}

Constant = \frac{1}{2}

Factor = \frac{h}{2}

6 0
3 years ago
An equilateral triangle of each side 4 cm​
MaRussiya [10]

Answer:

Each side of the triangle is 4cm and each angle is 60 degrees

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the LCM of n^3 t^2 and nt^4.<br><br> A) n 4t^6<br> B) n 3t^6<br> C) n 3t^4<br> D) nt^2
patriot [66]

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are n^3t^2 and nt^4.

The factored form of each term is

n^3t^2=n\times n\times n\times t\times t

nt^4=n\times t\times t\times t\times t

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t

LCM(n^3t^2,nt^4)=n^3t^4

The LCM of given terms is n^3t^4. Therefore the correct option is C.

8 0
3 years ago
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Serena has an art easel with sides of equal length. She opened the easel and place it on her desk. Classify the type of triangle
kotegsom [21]
It should be 10 cm thanks

4 0
3 years ago
The ratio of boys to girls in a group is 7:1. If there are 66 more boys than girls, work out how many girls there are
nevsk [136]

Answer:11

Step-by-step explanation:

Boys : girls=7:1

Sum of ratio=7+1=8

Let them number of girls be y

Then they number of boys=y+66

Total number of pupils=y+y+66

Total number of pupils=2y+66

Number of girls=(girls ratio)/(sum of ratio) x (total number of pupils)

y=1/8 x (2y+66)

Cross multiply

y x 8=2y + 66

8y=2y + 66

Collect like terms

8y-2y=66

6y=66

Divide both sides by 6

6y/6=66/6

y=11

The number of girls is 11

4 0
3 years ago
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