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Art [367]
3 years ago
13

Factor the following polynomial written in Standard Form. Select the correct answer from the choices listed below: 9d^2+12d+4

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

C

(3d + 2) (3d + 2)

= 9d^2 +6d +6d +4

= 9d^2 +12d +4

Kruka [31]3 years ago
4 0
The answer is (3d+2) (3d+2).
Steps:
Break the expression into groups:
(9d^2+6d)+(6d+4)
Factor out 3d from 9d^2+6d:
3d(3d+2)
Factor out 2 from 6d and 4: 2(3d+2)
=3d(3d+2)+2(3d+2)
Factor out common term (3d+2)
=(3d+2)(3d+2)

Hope this helps you! (:
-PsychoChicken4040
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Find the slope of the line that passes through each pair of points (13,-3),(-5,-5)
PIT_PIT [208]

Answer:

\boxed{\bold{\frac{1}{9} }}

Explanation:

(13,-3), (-5,-5)

<u>Find The Slope:</u>

<u />\bold{\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}}<u />

<u />\bold{\left(x_1,\:y_1\right)=\left(13,\:-3\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-5\right)}<u />

<u />\bold{m=\frac{-5-\left(-3\right)}{-5-13}}<u />

<u />\bold{ \ m \ = \ \frac{1}{9} }<u />

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3 years ago
What equivalent fractions could you write to add 1/2 and 2/3 ? EXPLAIN.
Anna11 [10]

Answer: 3/6 + 4/6

Step-by-step explanation:

So the key to this is you can only add fractions with the same denominator. As you can see from this question these denominators (2 and 3) are not the same so we need to change that. We can usually find a common denominator between the numbers but to save time the smallest number that both 2 and 3 go into is 6. so 1/2 becomes 3/6 because 1/2=3/6. And 2/3 becomes 4/6 because 4/6=2/3. Since that's true we can add both 3/6 and 4/6. So when adding fractions remember only add NUMERATORS do not add DENOMINATORS. so 3/6 and 4/6 = 7/6 NOT \neq 7/12.

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2 years ago
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Answer:

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Step-by-step explanation:

8 0
3 years ago
What is the expression for the below sequence (use n)<br><br> -3,-6,-9,-12
polet [3.4K]

Answer:

a_{n} = - 3n

Step-by-step explanation:

There is a common difference between consecutive terms, that is

- 6 - (- 3) = - 9 - (- 6) = - 12 - (- 9) = - 3

This indicate the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3 and d = - 3 , thus

a_{n} = - 3 - 3(n - 1) = - 3 - 3n + 3 = - 3n

The n th term is - 3n

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4 years ago
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