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denpristay [2]
3 years ago
5

Samir estimates the value of Three-fifths times 16.1. Which estimate is reasonable?

Mathematics
1 answer:
n200080 [17]3 years ago
6 0

Answer: 9

Step-by-step explanation:

\frac{3}{5}  \times 16.1 = 9.66

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15 3/4 divided by 7 5/7. Help
Evgen [1.6K]
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3 years ago
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Which of the following has no solution?
Sholpan [36]
The first one.
This statement is saying that x is less than zero and greater than zero at the same time. This is not possible. A number cannot be both negative and positive.
It's not the second one because this one includes equal to zero. It can be lass than or equal to zero and greater that or equal to zero because it can be ZERO.
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3 years ago
Question 9
Wittaler [7]

Answer:

Part A) Barbaroid will be executed

Part B) 75 more globin soldiers

Step-by-step explanation:

The army sizes of ORC leaders are

normally distributed with a mean of 5600 goblin soldiers and a standard deviation of 750 goblin soldiers.

The rule is that, if an Orc Leader shows up with an army of a z-score lower than

-1.5, he is immediately executed.

We want to determine whether Lord Barbaroid, an Orc Leader, who appears with an army of 4400 goblin soldiers,

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We find the z-score corresponding to 4400 using

z =  \frac{x -  \mu}{ \sigma}

We substitute x=4400 , the standard deviation and the mean to get:

z  =  \frac{4400 - 5600}{750}  =  - 1.6

Since Lord Barbaroid's z-score , -1.6 is less than -1.5 he will be executed.

Part B)

We want to find how many more goblin soldiers Lord Barbaroid have needed in order to NOT be executed and meet that Z-Score.

So we need to find the number of globin soldiers that corresponds to -1.5.

- 1.5 =  \frac{x - 5600}{750}

750 \times  - 1.5 = x - 5600

- 1125 = x - 5600 \\ x = 5600 - 1125

x = 4475

Therefore Barbaroid needed 4475-4400=75 more globin soldiers.

4 0
3 years ago
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Answer:

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