The maximum area the cow can gaze is 1256 square feet
<em><u>Solution:</u></em>
Given that a cow is tethered with a rope 20 feet long
<em><u>To find: Maximum area the cow can graze</u></em>
The maximum area the cow can gaze is the area of the circle with radius 20 feet
<em><u>The area of circle is given as:</u></em>
![area = \pi r^2](https://tex.z-dn.net/?f=area%20%3D%20%5Cpi%20r%5E2)
Where, "r" is the radius of circle and
is a constant equal to 3.14
<em><u>Substituting the values in above formula we get,</u></em>
![area = 3.14 \times 20^2\\\\area = 3.14 \times 400\\\\area = 1256](https://tex.z-dn.net/?f=area%20%3D%203.14%20%5Ctimes%2020%5E2%5C%5C%5C%5Carea%20%3D%203.14%20%5Ctimes%20400%5C%5C%5C%5Carea%20%3D%201256)
Thus the maximum area the cow can gaze is 1256 square feet
Check the picture below.
make sure your calculator is in Degree mode.
Answer:
(-1,3) x = -1, x = 3
Step-by-step explanation:
−5x−2=6x+9
Answer:
![d=5](https://tex.z-dn.net/?f=d%3D5)
Step-by-step explanation:
Distance Formula: ![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:
![d=\sqrt{(7-3)^2+(7-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%287-3%29%5E2%2B%287-4%29%5E2%7D)
![d=\sqrt{(4)^2+(3)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%284%29%5E2%2B%283%29%5E2%7D)
![d=\sqrt{16+9}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B16%2B9%7D)
![d=\sqrt{25}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B25%7D)
![d=5](https://tex.z-dn.net/?f=d%3D5)
The volume of the other side would be 390mm 3 as well