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nordsb [41]
2 years ago
14

a company that manufactures bicycles has a fixed cost of $80,000. it costs $100 to produce each bicycle. the total cost for the

company is the sum of its fixed cost and variable costs. write the total cost, C, as a fiction of the number of bicycles produced, x. then, find and interpret C(90).
Mathematics
1 answer:
frez [133]2 years ago
3 0

C(x) = 80000 + 100x is the total cost as function of number of cycles produced

C(90) = 89000 and it costs $ 89000 to produce 90 bicycles

<em><u>Solution:</u></em>

Given that, company that manufactures bicycles has a fixed cost of $80,000

Fixed cost = $ 80,000

Let x be the number of cycles produced

Let C(x) be the total cost as function of number of cycles produced

It costs $100 to produce each bicycle

Variable cost = 100 x number of cycles produced

variable cost = 100x

The total cost for the company is the sum of its fixed cost and variable costs

total cost = fixed cost + variable cost

C(x) = 80000 + 100x

Thus total cost as function of "x" is found

<em><u>Find and interpret C(90)</u></em>

Substitute x = 90 in C(x)

C(90) = 80000 + 100(90)

C(90) = 80000 + 9000

C(90) = 89000

Thus it costs $ 89000 to produce 90 bicycles

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Answer:

\fbox{ \sf{Perimeter \: of \: a \: rectangle = 10x - 2}}

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\star{ \sf{ \:  \: Length \: of \: a \: rectangle ( l )  = (2x - 5) }}

\star{ \sf{ \: Width \: of \:  a \: rectangle ( w ) = (3x + 4)}}

\star{ \sf{ \:  \: Perimeter \: of \: a \: rectangle =  ?}}

\boxed{ \bold{  \sf{Perimeter \: of \: a \: rectangle = 2(l + w)}}}

\hookrightarrow{ \sf{Perimeter \: of \: a \: rectangle = 2(2x - 5 + 3x + 4)}}

\text{Step \: 1 : \: Collect \: like \: term}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base}

\hookrightarrow{ \sf{2(2x  + 3x - 5 + 4)}}

\hookrightarrow{ \sf{2(5x - 5 + 4)}}

\text{Step \: 2  \: :  \: Subtract \: 4 \: from \: 5}

\text{Remember !\:  : the \: negative \: and \: positive \: integers \: are \: always \: subtracted \: but \: posses \: the \: sign \: of \: the \: bigger \: integer}

\hookrightarrow{ \sf{2(5x - 1)}}

\text{Step \: 3 \:  :  \: Distribute \: 2 \: through \: the \: parentheses}

\hookrightarrow{ \sf{2 \times 5x - 2 \times 1}}

\hookrightarrow{ \sf{10x - 2}}

\sf{∴ \: The \: perimeter \: of \: a \: rectangle = 10x - 2}

\text{Hope \: I \: helped !}

\text{Best \: regards ! }

~\text{TheAnimeGirl}

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