So we want to know the volume of a sphere in terms of pi if we know the area of the sphere is equal to A=9pi. So the area of the sphere is A=4*pi*r^2 and the volume V=(4/3)*pi*r^3. We can get the radius from the area: 9pi=4*pi*r^2 and we see the pi cancels out: 9=4*r^2. We divide by 4 and take the square root: r=sqrt(9/4)=3/2. So r=3/2 and we can input it into volume V.
V=(4/3)*(3/2)^3*pi=(4/3)*(27/8)*pi=(9/4)*pi.
So the volume of the sphere is V=(9/4)*pi cubic feet.
4 nickles
Explanation:
80=N+D
7.80=0.05N + 0.1D
D=80-N
7.80=0.05N + 0.1(80-N)
7.80=0.05N + 8 - 0.1N
0.1N + 7.80 = 8 + 0.05N
0.05N = 8-7.80
0.05N = 0.2
N= 4
Answer:
![A=379.94\ m^2](https://tex.z-dn.net/?f=A%3D379.94%5C%20m%5E2)
Step-by-step explanation:
Given that,
The radius of a circl is 11 m
We need to find the area of the circle. The forcemula for the area of a crcle is given by :
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
Put all the values,
![A=3.14\cdot11^{2}\\A= 379.94\ m^2](https://tex.z-dn.net/?f=A%3D3.14%5Ccdot11%5E%7B2%7D%5C%5CA%3D%09379.94%5C%20m%5E2)
So, the area of the circle is equal to
.
Step-by-step explanation:
first u start by writing it in
figure as stated in the question
6017