Question

Pn=1/3pn-1 and p4=108 , then p6= ? please show steps

Answer 1

$p_n=\dfrac13p_{n-1}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-2}\right)=\dfrac1{3^2}p_{n-2}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-3}\right)=\dfrac1{3^3}p_{n-3}$

and so on, up to

$p_n=\dfrac1{3^{n-4}}p_4=\dfrac{108}{3^{n-4}}$

which means

$p_6=\dfrac{108}{3^{6-4}}=\dfrac{108}9=12$