Given:
The volume of a cube-shaped box is cubic meter.
To find:
The perimeter of each of its faces.
Solution:
Let "a" be the side length of the cube shaped box. Then the volume of the box is:
It is given that the volume of a cube-shaped box is cubic meter.
Taking cube root on both sides, we get
Now, the perimeter of each face of a cube is:
Where, a is the side length of the cube.
Putting , we get
Therefore, the perimeter of each face of a cube-shaped box is 2 meters.
Is the 10 taking away 5 or was it meant to me 10.5 ?
Answer:
d. (9, 0)
Step-by-step explanation:
(x, y) so...
Where the line crosses the x-plane, x = 9
Since this is the x-intercept y will always equal zero
Therfore x-int = (9, 0)
=4m - 17+ 3m - 11
combine like terms
=(4m + 3m) + (-17 - 11)
=7m - 28
This can be factored/simplified by dividing everything by 7
=7(m - 4)
Hope this helps! :)
Cos theta = 75/115
theta = cos^-1 (75/115)
theta = 49.2 degrees