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SashulF [63]
3 years ago
7

Donna made $396 for 18 hours of work.

Mathematics
1 answer:
amm18123 years ago
5 0

Answer:

$286

Step-by-step explanation:

396/18 = $22 per hr x 13 hrs = $286

Plz give Brainliest

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A submarine was traveling along the surface of the ocean and decides to dive. If the dive angle is 28° with the horizontal surfa
Alex_Xolod [135]

Answer:

1.5 nautical miles

Step-by-step explanation:

See the attached diagram.

The submarine starts to dive at point A and diving along AB.

If the distance traveled underwater i.e. AB = 1.7 Nautical miles and C is the point directly above its current position at B.

Then Δ ABC is a right triangle having ∠ BAC = 28° {Given}

So, using trigonometry we can write  

\cos 28 = \frac{AC}{AB} = \frac{AC}{1.7}

⇒ AC = 1.7 \times \cos 28 = 1.5 nautical miles.

Therefore, the surface distance that the submarine travels is 1.5 nautical miles. (Answer)

3 0
2 years ago
the providence children muesuem installed a fence around the perimeter of the propety. the propety is a rectangle. one side is 3
mash [69]
Its a rectangle so two sides are equal and both sides that are opposite of each other are equal. So two sides are 37. Then you add them together to get 74, then subtract it from 164 to get 90 the rest of the fence length. Then divide it by two to get 45 which is the other side lengths, so it would be a 37 by 45 rectangle one side would be 37 while the other two are 45.
7 0
3 years ago
Use the parabola tool to graph the quadratic function f(x) =-5x2 -2
enot [183]
Your first point would be on (0, 2), the vertex. Then, put a point on (-2, 22). Hope that helps!
3 0
3 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
2 years ago
Timothy has a fenced-in garden in the shape of a rhombus. The length of the longer diagonal is 24 feet, and the length of the sh
Drupady [299]
One side of the fenced-in garden is 15 ft
7 0
3 years ago
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