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jonny [76]
3 years ago
15

What is the series in sigma notation? -5 + (-1) + 3 + 7 + 11?

Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
For the series:
- 5 + ( - 1 ) + 3 + 7 + 11
common difference between the numbers is 4 and a 1 = -5
The series in sigma notation:
  4
  ∑   ( 4 i - 5 )
i =0
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What is the inverse of the function f(x) = 4x + 8?
morpeh [17]

Answer:

(A) h(x) = 1/4x -2

Step-by-step explanation:

Given: f(x)=4x+8

Rewrite with y: y=4x+8

Switch x and y: x=4y+8

Solve for y: x-8=4y

(x-8)/4=y

1/4x-2=y

y=1/4x-2

This means that h(x) = 1/4x -2 is the correct answer

8 0
3 years ago
SOS!!
wlad13 [49]

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4 0
3 years ago
Park city Utah gets 43.8inches of rain per year. Usually 45% of that amount falls in November. How much rain falls in those mont
aliina [53]
43.8 = 100%
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3 0
3 years ago
How many solutions exist for the given equation?
katrin2010 [14]

1(x + 12) = 4x - 1\\x+12=4x-1\\13=3x\\x=\frac{13}{3} \\x=4\frac{1}{3}

This equation has only one solution

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

P.S. Hello from Russia

7 0
3 years ago
Read 2 more answers
Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: y=mx+b where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation  y=mx+b where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

y=mx+b\\y=-\frac{2}{3}x+3

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

5 0
3 years ago
Read 2 more answers
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