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balu736 [363]
3 years ago
12

Solve x3 = 1 over 8.

Mathematics
2 answers:
marishachu [46]3 years ago
8 0
X^3=1/8

x=(1/8)^(1/3)

x=1/2
Kaylis [27]3 years ago
5 0

Answer:

The simplified form of the provided equation is 1/2.

Step-by-step explanation:

Consider the provided equation.

x^3=\frac{1}{8}

8 can be written as 2³

1 can be written as 1³

Therefore the provided equation can be written as:

x^3=\frac{1^3}{2^3}

x^3=(\frac{1}{2})^3

x=\frac{1}{2}

Hence, the simplified form of the provided equation is 1/2.

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CAN SOMEONE HELPP PLZZ I POSTED THIS QUESTIONS LIKE 50 TIMES AND NO ONE ANSWEREDD
Nady [450]

Answer:

y = (x+1) + 1

Step-by-step explanation:

y = (x+1) + 1

y=x Vertical translation UP 1 unit and further Up 1 unit makes it UP 2 units,

y = (x+1) + 1      x≤-1    : The purple ray

4 0
3 years ago
Lisa sold costume jewelry at a bazaar. The first hour she sold 2 bracelets and 3 rings for a total of $36.00 later a customer bo
saw5 [17]
2x + 3(6) = 36

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7 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
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nadezda [96]

Answer:

12.85 m

Step-by-step explanation:

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\frac{x}{360}  \times \pi \: d

Since the figure is a semicircle, we know the central angle is 180, so plug that in for x. We also know the diameter, which is 5. So plug that in for d. Once you get the arc length, add 5 to it. 5 is the diameter and is part of the perimeter

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PLEASE HELP ONE QUESTION!!!!!! PLEASEEEEE
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VW=CD since they are congruent figure, so CD=6
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