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3 years ago

Which represents all the values of x that make the rational expression 2x-4 over x-5 undefined?

Mathematics

1 answer:

mixas84 [53]3 years ago

5 0

For this case we have the following expression:

$\frac {2x-4} {x-5}$

By definition, we have the expression undefined when the denominator is 0.

So:

$x-5 = 0$

Adding 5 to both sides of the equation:

$x-5 + 5 = 5\\x = 5$

Thus, the expression is undefined when $x = 5.$

Answer:

Option B

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-X² + 5x - 6 = 2<br> Using the quadratic formula

Ivenika [448]

$-x^2+5x-6=2\\-x^2+5x-6-2=0\\-x^2+5x-8=0\\$

↝ Form into $ax^2+bx+c = 0$ where a > 0 (Optional)

$x^2-5x+8=0$ ↝ Multiply -1 for both sides.

↝ Then proceed with the Quadratic Formula.

x = [-b ± (√b²-4ac)]/2a ↝ Quadratic Formula

$x=\frac{-(-5)+-\sqrt{(-5)^2-4(1)(8)}}{2(1)}\\x=\frac{5+-\sqrt{25-32}}{2}\\$

↝ As you can see that inside the square root, the numbers cannot be negative. Therefore, the solutions are imaginary.

↝ Solution with Real Numbers System ↝ There are no real solutions.

↝ Solution with Complex Number System ↝

$x=\frac{5+-\sqrt{25-32}}{2}\\x=\frac{5+-\sqrt{-7}}{2}\\x=\frac{5+-\sqrt{7}i }{2}$

Therefore, the answer for Complex Number System is (5±√7i)/2

3 0

3 years ago

In the figure below, the two adjacent polygons are regular. What is the measure of ∠ABC?

Dennis_Churaev [7]

Answer:

= 150°

Step-by-step explanation:

Since the polygons are regular, certain mathematical assumptions would help us here.

A square is a quadrilateral with all it's 4 sides equal and all it's angles equal.

Sum of angles of a regular quadrilateral = 360.

Therefore, a single angle = 360/4

= 90°.

The Triangle is adjacent to the side of the square. We will thus assume it's an Equilateral triangle.

For an equilateral triangle, all it's 3 angles = 180.

A single angle = 180/3

= 60°.

With this,

Angle ABC = 90° + 60=

= 150°

7 0

3 years ago

Suppose that you are interested in estimating the average impact a job training program has on wages. After controlling for obse

Ede4ka [16]

Answer:

False

Step-by-step explanation:

From the question we are told that

The coefficient for the training is $r = 0.55$

The standard error is $SE = 1.06$

The confidence level is 95%

Generally the level of significant is mathematically represented as

$\alpha =( 100 -95)\%$

=> $\alpha = 0.05$

Generally the critical value of $\alpha = 0.05$ obtained from the normal distribution table is $Z_{0.05} = 1.645$

Generally the test statistics is mathematically represented as

$t = \frac{r }{SE}$

=> $t = \frac{0.55}{1.06}$

=> $t = 0.5189$

Generally given that the $t < Z_{\alpha }$

Hence there is no sufficient evidence to conclude that the program has a positive and statistically significant impact on wages at a 95% confidence level.

So the answer is False

3 0

4 years ago

Write 7/8 as a product of a whole number and unit fraction

damaskus [11]

7/8 = 14*(1/16)

Maybe you're expecting
7/8 = 7*(1/8)

7 0

3 years ago

Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul

Ivahew [28]

Answer:

a) $P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

b) $P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

c) $P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

d) $P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

e) $P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

Step-by-step explanation:

For this case we have the following cumulative distribution function:

$F(x) = 0 , x$

$F(x) = 0.7, 1 \leq x$

$F(x) = 0.9, 4 \leq x$

$F(x) = 1, x \geq 7$

Part a

We want this probability:

$P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

Part b

We want this probability:

$P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

Part c

We want this probability:

$P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

Part d

We want this probability:

$P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

Part e

We want this probability:

$P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

7 0

3 years ago