You have decided to buy a new car, but you are concerned about the value of the car depreciating over time. You do some research
on the model you are looking at and obtain the following information:
Suggested retail price - $18,790
Depreciation per year - $1385 (It is assumed that this value is constant.)
The following table represents the value of the car after n years of ownership.
2 answers:
<span>The answer should be set up like so:
3125 = 3200*(d)^3
3125/3200 = d^3
3-root (3125/3200) = d
d = 0.992125657...
1 - d = 0.007874...
Therefore it depreciates at about 0.8% monthly
To find the depreciation 6 months from now, or 9 months from the beginning:
v = 3200 (d)^9
= 2980.232239...
So after 9 months the car would be about $2980.23</span><span>
</span>
Answer: D on edge
Step-by-step explanation:
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Answer:
(a) 36
(b) y = 36x-31
Step-by-step explanation:
(a) dy/dx = 18x
slope of tangent at (2, 41) = 18(2)
= 36
(b) using y-y1 = m(x-x1)
y-41 = 36(x-2)
y = 36x-31
Answer:
36°
Step-by-step explanation:
< EAB = 180 - (360/5) = 180-72=108°
so, < AEB = (180-108)/2 = 72/2 = 36°
Answer:
m`1 = 43` 2,3
m<2 1/12*
and m <3 = 1,3/2
Step-by-step explanation:
Answer:
k x 1/2
Step-by-step explanation:
because k x 1/2 = k/2
jeez that looks really hard
Step-by-step explanation:
