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SpyIntel [72]
3 years ago
6

Which of these are rational numbers?

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

1. 3\2

2.\sqrt{11}

3.-13

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What are the values of x and y if this equation is true?<br><br> 22(x + yi) + (28 + 4i) 72 – 62i
ASHA 777 [7]

Answer:

x = 2

y = -3

Step-by-step explanation:

The given equation is,

22(x + yi) + (28 + 4i) = 72 - 62i

By solving this equation further,

22x + 22yi + 28 + 4i = 72 - 62i

(22x + 28) + (22y + 4)i = 72 - 62i

Now both the sides of the equation is in the form of complex number,

By comparing real and imaginary parts given on both the sides,

22x + 28 = 72

22x = 72 - 28

22x = 44

x = 2

22y + 4 = -62

22y = -62 - 4

22y = -66

y = -3

Therefore, x = 2 and y = -3 are the values for which the given equation is true.

8 0
3 years ago
What is 42 divided by 6?
irakobra [83]
42/6 is 7 because seven 6s go in 42
6 0
3 years ago
Read 2 more answers
Find the HCF of 30x²y²z³​
Gennadij [26K]

Answer:

The greatest common factor or highest common factor of any set of numbers is the largest possible number which divides both the numbers exactly. HCF of 24 ..

Step-by-step explanation:

6 0
3 years ago
How do I use the arc length to find the circumference ?
Mashutka [201]
<span>arc length   =   circumference • [central angle (degrees) ÷ 360]

Solving this equation for circumference:
</span>
<span>circumference = arc length / (central angle / 360)

</span><span>circumference = 12 / (85/360)

</span>circumference = 12 / <span><span>0.2361111111 </span>
</span>
<span>circumference = </span> <span> <span> <span> 50.8235294118 </span> </span> </span>

Source:
http://www.1728.org/radians.htm


8 0
3 years ago
Combine the like terms to create an equivalent expression: <br><br>−4p+(−6p)
Y_Kistochka [10]

THE ANSWER IS -10P.

Step-by-step explanation:

USING BY MULTIPLICATION RULE.

minus × plus = minus

then minus × minus = plus.

so we add the 4p+6p= -10p.

why -10p is come it means THE BIGGER NUMBER SIGN IS MINUS. So it's comes -10p.

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
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