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kicyunya [14]
3 years ago
10

In a toy store, the ratio of the number of dolls to teddy bears is 6:7. If the store has 120 dolls, how many teddy bears are the

re?
Mathematics
1 answer:
VMariaS [17]3 years ago
6 0
Dolls : teddy bears
6 : 7

if 120 dolls are equal to 6 portions,
7 portions,
(120/6) * 7
140 teddy bears
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A right triangle has leg lengths of 9 units and 12 units. Write an equation that can be
LenKa [72]
<h2>The Pythagorean Theorem</h2>

The Pythagorean Theorem: a^2+b^2=c^2

  • <em>a</em> and <em>b</em> are the two legs in a right triangle
  • <em>c</em> is the hypotenuse (the longest side of a right triangle; opposite the 90° angle
  • <em>*keep in mind that this theorem applies only to right triangles</em>

<h2>Solving the Question</h2>

We're given:

  • Legs = 9 units and 12 units
  • Hypotenuse = <em>c</em>

<em />

Plug these measurements into the Pythagorean theorem:

a^2+b^2=c^2\\9^2+12^2=c^2

⇒ Combine like terms:

81+144=c^2\\c^2=225

<h2>Answer</h2>

c^2=225

4 0
2 years ago
G in how many ways can first, second, and third prizes be awarded in a contest with 335 contestants?
vladimir1956 [14]
Let the number of contestants is n and the prizes is r
the number of ways is npr = 335p3 = 37259370 ways

8 0
3 years ago
There were 48 blue, 48 green and 48 yellow crayons. Also there were 72 red crayons and 120 colored pictures. What is the largest
Elis [28]
48 sets i believe since there are only 48 maximum of blue, green and yellow crayons therefore the 49th set would only contain a red crayons and a picture
3 0
2 years ago
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£8001 is shared equally between 9 people. How much does each person get?
Alika [10]
£888.9 because you can divide £8001 buy 9
5 0
2 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
1 year ago
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