Question

A carnival has two payment options. Plan A, you pay $10 admission plus $3 for each ride. Plan B, you pay a $20 admission plus $1 for each ride. Write an inequality that would express the situation where plan B is the best buy,

Answer 1

Answer:

$x+20$

Step-by-step explanation:

Let x represent the number of rides.

We have been given that a carnival has two payment options.

In Plan A, you pay $10 admission plus $3 for each ride. The total cost for x rides using plan A would be $3x+10$.

In Plan B, you pay a $20 admission plus $1 for each ride.The total cost for x rides using plan B would be $x+20$.

Now we will show that plan B is best buy by showing that cost of x rides in plan B is less than plan A as:

$x+20$

Therefore, our required inequality would be $x+20$.

Answer 2

Let x = # of rides

Plan A: 10 + 3x

Plan B: 20 + x

if x < 5 rides then plan A is better buy
if x = 5 both plans are the same
if x > 5 then plan B is the best buy

Prove:
x = 6 (rides)

plan A: 10 + 3x = 10 + 3(6) = 10+18 = $28
plan B: 20 + x = 20 + 6 = $26