Answer:
Step 3 i think because 10-7+7=13 because if u do that problem u actually get 10 instead of 13
Step-by-step explanation:
because 10-7+7=13 because if u do that problem u actually get 10 instead of 13
To prove <QPR = <QRP we have to prove ΔPTR ≅ ΔRSP
Let T be the mid point of PQ and S be the mid point of QR
line joining T and S is TS parallel to PR
Triangle PTR and triangle RSP have same base, one side equal and between same parallel are congruent.
Therefore ΔPTR ≅ ΔRSP by CPCTC <QPR = <QRP
So we can cnclude that PQR is an isosceles triangle.
Using a system of equations, the expression or the number of touchdowns he scored in his second year is: 2(t - 1)
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In his first year, he scored t touchdowns. In the second, the amount was two less than twice the number of touchdowns he scored in his rookie year, hence the expression is:
2t - 2 = 2(t - 1)
More can be learned about a system of equations at brainly.com/question/24342899
Answer:
He makes $1 every 2 minutes
Step-by-step explanation:
If you break it down 60 minutes is in an hour and he works for 3 hours total so you multiply 60×3 which is 180 that's how many minutes he works for. Then you take the money he made and take the minutes and divide it by the money 180÷90=2 so he make $1 every 2 minutes
Problem 7
<h3>Answer: Choice A) 7</h3>
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Work Shown:
p(x) = x^4+x^3-kx-x+6
If (x-2) is a factor of p(x), then x = 2 is a root of p(x). This is a special case of the remainder theorem.
This means p(2) = 0
Replace every x with 2 and solve for k
p(x) = x^4+x^3-kx^2-x+6
p(2) = 2^4+2^3-k(2)^2-2+6
p(2) = 16+8-4k-2+6
p(2) = 28-4k
0 = 28-4k .... replace p(2) with 0
4k = 28
k = 28/4
k = 7
The polynomial
p(x) = x^4+x^3-7x^2-x+6
has the factor (x-2)
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Problem 8
<h3>Answer: D) 40</h3>
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Work Shown:
Check out the diagram below to see the synthetic division table. We're after the remainder which is highlighted in yellow.
An alternative is to use direct substitution
p(x) = 2x^4+4x^3-x^2-5
p(-3) = 2(-3)^4+4(-3)^3-(-3)^2-5 ... replace every x with -3
p(-3) = 2(81)+4(-27)-9-5
p(-3) = 162-108-9-5
p(-3) = 40
This helps confirm we got the right remainder and the right answer.