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Mashutka [201]
3 years ago
15

I cant figure out 17 :3 and 68 :12 are equivalent

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0

First of all, the fractions are equivalent:

\dfrac{17}{3} = \dfrac{17\cdot 4}{3\cdot 4} = \dfrac{68}{12}

As for the second part, we have

\dfrac{3 \text{ slices}}{2\text{ minutes}}=\dfrac{3\cdot 5 \text{ slices}}{2\cdot 5\text{ minutes}} = \dfrac{15 \text{ slices}}{10\text{ minutes}}

sleet_krkn [62]3 years ago
5 0

Answer:

17:3 is 68:12 simplified

15 slices will be eaten in 10 minutes

Step-by-step explanation:

first off 17:3 is 68:12 simplified (both 68 and 12 go into 4 resulting in 17 and 3)

you have to divide 10 by 2 which will give you 5

and then multiply by 3

to get 15

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3 years ago
The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu
PSYCHO15rus [73]

Answer:

a) I(95,50) = 73.19 degrees

b) I_{T}(95,50) = -7.73

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

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I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19 degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is I_{T}(T,H). So

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H

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8 0
3 years ago
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Answer:

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7 0
3 years ago
Read 2 more answers
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